The following construction was defined by Wang in [Wan95]
Given two (compact) groups and
, we can construct their direct product. Such a construction is generalized to the quantum case as the tensor product of quantum groups. Here, we have
. In particular, the two factors
and
commute.
If we start with some pair of free compact quantum groups (such as the free orthogonal quantum group ), we would like to generalize the direct product in a way, that the resulting C*-algebra will again be as free as possible. To achieve that, we replace the tensor product by the C*-algebraic free product.
Let and
be compact quantum groups. We define [Wan95] their dual free product
to be the quantum group with underlying C*-algebra
and comultiplication the unique unital
-homomorphism satisfying
Formally, we should rather write ,
, where
and
are the canonical inclusions into
.
Let and
be compact matrix quantum groups. Then
is also a compact matrix quantum group. It is a matrix realization of the dual free product of and
as defined above.
Given two discrete groups ,
, we can construct their free product
. Note that the above definition of the dual free product should not be interpreted this way, because the freeness in case of the dual free product appears in the C*-algebra multiplication, not in the comultiplication. This is the reason for the word dual in the name. (And indeed, free product of the compact groups is a group that is never compact; in contrast, dual free product of two compact groups is a compact quantum group, but not a group).
However, dualizing the definition above, we may indeed generalize the definition of a free product to the case of discrete quantum groups.
Let and
be discrete quantum groups. We define their free product to be the quantum group
.
In case when and
are discrete groups, the above defined direct and free product exactly corresponds to the classical construction for groups.
The notation using the hat and calling the product dual free product is rather new. It was first used probably in [DFSW13]. Some authors omit the word dual and denote the product just by asterisk . In most cases, it should be clear, which product is meant – whether the dual free product or the free product – since the former is defined only in the compact case, whereas the latter only in the discrete case. It may, however, cause some confusion if one works with finite (quantum) groups.
Let and
be compact quantum groups. Let
and
be complete sets of irreducible representation of
and
. Denote by
and
the embeddings of
and
into
, respectively, and denote
and
. Then a complete set of irreducible representations of
is formed by the trivial representation together with
where are non-trivial representations such that the sets
and
alternate, so if
, then
and vice versa. [Wan95]
Let and
be compact quantum groups and let
,
, respectively be the corresponding Haar states. Then the Haar state on
is given by the free product
. [Wan95]